Bulletproof SSL and TLS by Ivan Ristić PDF

By Ivan Ristić

ISBN-10: 1907117040

ISBN-13: 9781907117046

Figuring out and deploying SSL/TLS and PKI to safe servers and net purposes, through Ivan Ristić

For process directors, builders, and IT defense execs, this publication presents a complete insurance of the ever-changing box of SSL/TLS and net PKI. Written by way of Ivan Ristić, a safety researcher and writer of SSL Labs, this booklet will educate you every little thing you must recognize to guard your structures from eavesdropping and impersonation assaults.

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Extra info for Bulletproof SSL and TLS

Example text

We conclude by noting that most proofs in modern cryptography use what may be called the red uctionist a pproach. Given a theorem of the form The reductionist approach. "Given that A ssumptio n X is true, Co nstruction Y is secure ac­ cording to the given definitio n", a proof typically shows how to reduce the problem given by Assumption X to the problem of breaking Construction Y. More to the point , the proof will typically show (via a constructive argument) how any adversary breaking 27 Introduction Construction Y can be used as a sub-routine to violate Assumption will have more to say about this in Section 3.

Assume next that for every distribution over M, every mo, m1 E M, and every c E C it holds that Pr [C = c I M = mo] = Pr[C = c I M = m1 ] . Fix some distribution over M, and an arbitrary mo E M and c E C. Define p clef Pr [C = c I M = mo] . Since Pr [C = c I M = m] - Pr [C = c I M = mo] - p for all m, we have Pr [C --:- c] = = L mEM L Pr[C= c I M= m] · Pr [M = m] p Pr [M= m] · mEM =p· :Z::: Pr [ M- m] =p Pr [C= c I M= mo ] . = Since mo was arbitrary, we have shown that Pr [C= c] = Pr [C = c I M = m] for all c E C and m E M.

Would encrypt the message tellhimaboutme to GDOOKVCXEFLGCD. A brute force attack on the key space for this cipher takes much longer than a lifetime, even using the most powerful computer known today. However, this does not necessarily mean that the cipher is secure. In fact, as we will show now, it is easy to break this scheme even though it has a very large key space. , the text is grammatically-correct English writing, not just text written using characters of the English alphabet) . It is then possible to attack the mono-alphabetic substitution cipher by utilizing statistical patterns of the English language (of course, the same attack works for any language) .

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